A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.250 m/s and acceleration -0.270 m/s2. Suppose it moves with constant acceleration for 4.90 s.
(a) Find the position of the particle after this time.
m

(b) Find its velocity at the end of this time interval.

Question

A particle moves along the x axis. It is initially at the position 0.180 m, moving with velocity 0.250 m/s and acceleration -0.270 m/s2. Suppose it moves with constant acceleration for 4.90 s.
(a) Find the position of the particle after this time.
m

(b) Find its velocity at the end of this time interval.

anonymous · Answer

direct usage of equations of motion... can u try it  here.. ?

anonymous · Answer

i think so, @Mashy 
but I'm missing $$\omega$$

anonymous · Answer

what! ? :O its a straight line motion buddy!

anonymous · Answer

i know, i can do it in a straight line with no problem, but i was wondering if there is an alternative way. Because it's based on harmonic oscillation and motion

anonymous · Answer

its not harmonic motion.. its just simple 1 dimensional constant acceleration motion

anonymous · Answer

I know, can you try part c and d for me @Mashy ?

anonymous · Answer

where is C and D? :P

anonymous · Answer

lol sorry
Next, assume it moves with simple harmonic motion for 4.90 s and x = 0 is its equilibrium position. (Assume that the velocity and acceleration is the same as in parts (a) and (b).)
(c) Find its position.

(d) Find its velocity at the end of this time interval.