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Mathematics 8 Online
OpenStudy (katherinesmith):

what's the best way to solve this system of equations?

OpenStudy (katherinesmith):

5x + 3y = 46 2x + 5y = 7

OpenStudy (jdoe0001):

I'd use elimination

OpenStudy (katherinesmith):

every time i try to use elimination it turns out with numbers that are none of my choices

OpenStudy (owlcoffee):

Let's do it by sustitution: 5x + 3y = 46 2x + 5y = 7 Let's pick a equation and solve it for y: \[5x+3y=46\] Then: \[y=\frac{ 46-5x }{ 3 }\] And let's substitute in the other equation: \[2x+5(\frac{ 46-5x }{ 3 })=7\] try solving that equation for x.

ganeshie8 (ganeshie8):

solution should not depend on the method u use to solve it

OpenStudy (owlcoffee):

Sometimes one method is more convinient to use than an other.

ganeshie8 (ganeshie8):

yup ^

OpenStudy (katherinesmith):

i literally don't even know how to solve that equation..

OpenStudy (katherinesmith):

can you walk me through it

ganeshie8 (ganeshie8):

to solve x, u must isolate x

OpenStudy (katherinesmith):

FYI, the answer has to be one of these 4 things (2, 10) (3, 4) (3, 11) (11, -3)

OpenStudy (jdoe0001):

\(\large \begin{array}{llrrrr} 5x + 3y = 46 & \times 2 \implies &10x &+ 6y &= &92\\ 2x + 5y = 7 & \times -5 \implies &-10x &+ -25y &= &-35 \end{array}\)

ganeshie8 (ganeshie8):

lets start wid a simple thing, x+3 = 7 u can solve this, eh ?

OpenStudy (katherinesmith):

x = 4

ganeshie8 (ganeshie8):

thats all it needs to solve anything

OpenStudy (katherinesmith):

... still don't know how to do it with that fraction

ganeshie8 (ganeshie8):

lets take another example, before doing the actual problem \(\large x + \frac{3}{19} = 10\) can u solve this ?

OpenStudy (katherinesmith):

x = 10 - 3/19

ganeshie8 (ganeshie8):

Awesome ! \(\large 2x+5(\frac{ 46-5x }{ 3 })=7 \)

OpenStudy (katherinesmith):

i do not know how to do that like seriously

ganeshie8 (ganeshie8):

you refering to this equation, right ?

OpenStudy (katherinesmith):

yes

ganeshie8 (ganeshie8):

first observe that x is not isolated yet,

OpenStudy (jdoe0001):

\(\large \begin{array}{llrrrrll} 5x + 3y = 46 & \times 2 \implies &10x &+ 6y &= &92\\ 2x + 5y = 7 & \times -5 \implies &-10x &+ -25y &= &-35\\ \hline &&0&-19y& = & 57&\\\implies y = -\cfrac{57}{19} = 3 \end{array}\)

ganeshie8 (ganeshie8):

\(\large 2\color{red}{x}+5(\frac{ 46-5\color{red}{x} }{ 3 })=7 \)

OpenStudy (jdoe0001):

should be the same using substitution though

OpenStudy (katherinesmith):

jdoe0001 why is there an = 3 on the end of that

ganeshie8 (ganeshie8):

ok lets wait for jdoe to finish, we can continue after that

OpenStudy (jdoe0001):

ohh hamme. -3 rather

OpenStudy (jdoe0001):

\(\large \begin{array}{llrrrrll} 5x + 3y = 46 & \times 2 \implies &10x &+ 6y &= &92\\ 2x + 5y = 7 & \times -5 \implies &-10x &+ -25y &= &-35\\ \hline &&0&-19y& = & 57&\\ \implies y = -\cfrac{57}{19} = -3 \end{array}\)

OpenStudy (katherinesmith):

look i really don't know how to isolate the x with that fraction like i really don't. like i don't understand any probably never will so i'm giving up on that method. i understand that i'm supposed to isolate the x but i don't know how to frickin do it on that type of problem. i'm sorry. it just doesn't click.

OpenStudy (katherinesmith):

x is 11 y is -3. got it. thank you both

ganeshie8 (ganeshie8):

if u dont want to learn its fine :) i thought you're struggling, and trying to understand it

OpenStudy (katherinesmith):

i am struggling and i need help but i just suck at math.

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