Question

A subway train starting from rest leaves on with a constant acceleration. At the end of 9.34s it is moving at 15.0374 m/s. What is the train's displacement in the first 5.99628s of motion? Answer in units if m

Answer 1

I think the Total time is,T=9.34 s
Initial speed, u=0
Final speed, v = 15.0374 m/s

Answer 2

Using fundamental motion equation

v=u+aT

a=(v-u)/T

=(15.0374-0)/9.34

=1.61 m/s^2

Displacement at 5.99628 s

s=ut+(1/2)at^2

=0+(1/2)*(1.61)*(5.99628)^2

=28.944 m

Answer 3

Thanks so much for the help that's right :)

Answer 4

your welcome :)