Question

Ether, the well known anesthetic, has a density of 0.736 g/cm^3. What is the volume, in litter, of 225.0 grams of ether?

Answer 1

do you undertand this

Answer 2

Density = mass/volume. So if the density is .736g, then we would need to solve this equation:
\[0.736=\frac{ 225.0 }{ V }\]

Answer 3

165.6 is that it

Answer 4

No, it isnt actually. You need to get V out of the denominator of that fraction in order to solve for it. To get V out of the bottom, you multiply both sides by V.
\[0.736V = \frac{ 225.0V }{ V }\implies 0.736V = 225.0\]
Now that we have 0.736V = 225.0, we can divide both sides by 0.736 to isolate V:

\[\frac{ 0.736V }{ 0.736 }=\frac{ 225.0 }{ 0.736 }\implies V = \frac{ 225.0 }{ 0.736 }\]So that would be the division you need to do.

Answer 5

305.7065

Answer 6

right

Answer 7

Right :3

Answer 8

and the units would be cm^3

Answer 9

right

Answer 10

Yes it would be :3

Answer 11

thanks

Answer 12

Mhm, np.

Answer 13

can you help me with one mor e

Answer 14

If I know how to do it then sure, lol.

Answer 15

an automobile manufacture claims that is sedan uses only 6.0 L of gasoline to travel 100 km. How many miles per gallon of gasoline could be expected from this car
( 1 mile = 1.61 km)

Answer 16

Well, this requires us to have a liters to gallons conversion, too.

Answer 17

It wasnt given to you?

Answer 18

Professor Google it is.

Answer 19

Okay, so 1 gallon = 3.79L

Answer 20

okay

Answer 21

So what we do is we find conversion factors, for example 1 gallon = 3.79L, 1 mile = 1.61km, etc, and we multiply those conversion factors by our original information. So what we're initially told is 6.0L can get you 100km. So what I want to do is turn this into a fraction:
\[\frac{ 6.0L }{ 100km }\]Now I can decide to change km to miles or liters to gallons first, it doesnt matter. So Ill do liters to gallons first. The conversion factor is 1g = 3.79L. So now I want to turn this into a fraction and multiply it by the current fraction we have:

\[\frac{ 6.0L }{ 100km }*\frac{ 1gal }{ 3.79L }\]Now the reason I wrote it the way I did is because when I multiply, I want the units to cancel. I dont want liters anymore, I want gallons. So when I multiply by the conversion factor of 1gal = 3.79L, I put the fraction as such so that Liters will cancel out top and bottom. SO doing that multiplication, that gives me:
\[\frac{ 6.0gal }{ 379km }\]Now I finally want to change km to miles. So now Ill take my other conversion factor of 1 mile = 1.61km, and multiply this by what we currently have. Now, we want the km to go away, so that means when we multiply, I want to have km on top and km also on bottom. That means Im multiplying liek this:

\[\frac{ 6.0gal }{ 379km}*\frac{ 1.61km }{ 1mile }\]When we multiply these, the km will cancel top and bottom and then it's just calculator work. \[\frac{ 9.66gal }{ 379mil }\]Now this gives us the amount for 9.66 gallons, but we want the amount for 1 gallon. So that requires us to set up a proportion. The proportion would be set up like this:

\[\frac{ 9.66gal }{ 379mil }= \frac{ 1gal }{ x }\]So basically this says that, assumign the ratio is the same, if 9.66 gallons = 379 miles, then 1gal = x miles. This can then be solved by cross-multiplying. So 9.66 multiplies across by x and 1 gallon multiplies straight across by 379 miles. Doing the cross-multiplication gives us:
\[9.66x = 379\]So then solving for x gives me:
\[x=\frac{ 379 }{ 9.66 }\approx 39.23\]So that means I would get approximately 39.23 miles per gallon.

Answer 22

ohh wow thanks

Answer 23

As long as it makes sense xD

Answer 24

thanks again it made sense

Answer 25

Sure ^_^