Question

A car traveling initially at 8.9 m/s accelerates at the rate of 0.875 m/s^2 for 2.9s

What is its velocity at the end of the acceleration?

Answer 1

V= V(initial) + at
V(initial)= 8.9 m/s
a=0.875 m/s^2
t=2.9s
V= ?

V= 8.9 + (0.875)(2.9)
V= 8.9+ 2.5375
V= 11.4375m/s

Answer 2

\[V=V_0+a·t=8.9+0.875·2.9=11.44 m/s\]

Answer 3

Thanks for the help :)

Answer 4

you are welcome