Question

2√2xˆ2 + 2√5x = 0

Answer 1

\[2\sqrt{2^{2}}+2\sqrt{5x}\]
we have some radicals, but the proceidure requires factoring,
Want me to guido you through it?

Answer 2

the problem is \[2\sqrt{2x ^{2}}+2\sqrt{5x}=0\] and yes please

Answer 3

much better:
Let's begin by applying a common factor:
\[2(\sqrt{2x ^{2}}+\sqrt{5x})=0\]

Answer 4

we would pull out an x

Answer 5

\[\sqrt{x}*(2\sqrt{2}*\sqrt{x}+2\sqrt{5})=0\]

Answer 6

x^1/2=0
OR
\[2\sqrt{2x}=-2\sqrt{5}\]

Answer 7

on squareing both sides
\[4*2x=4*5\]

Answer 8

8x=20
x=5/2