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Mathematics 20 Online
OpenStudy (lukecrayonz):

If y=1/x^2, find dy/dx|x=-2

OpenStudy (lukecrayonz):

Just do the deriv and input x=-2?

OpenStudy (psymon):

Yep.

OpenStudy (lukecrayonz):

1/4 :)

OpenStudy (psymon):

Looks good to me.

OpenStudy (lukecrayonz):

How would you find the deriv to this?

OpenStudy (lukecrayonz):

Without the whole x+h dealio

OpenStudy (psymon):

Well, this kind of derivative in particular has a pretty fast way of doing it. The long way would be that you need to make the x^2 into a negative exponent like this: \[\frac{ 1 }{ x ^{2} }=x ^{-2} \] Then you would use the power rule formula for derivatives, which is: \[x ^{n}\implies nx ^{n-1} \]So with n being -2, we use the formula to get: \[-2x ^{-3} =\frac{ -2 }{ x ^{3} } \] These fraction derivatives have a pattern tot hem, though, that make them a little easier.

OpenStudy (lukecrayonz):

That makes a lot of sense:)

OpenStudy (lukecrayonz):

Okay and how about finding a line tangent?

OpenStudy (lukecrayonz):

Oh wait a little different.. one sec:O

OpenStudy (lukecrayonz):

For the function, find the pts on the graph at which the tangent line is horiziontal. If none exist, state that fact.

OpenStudy (psymon):

Well, the derivative is a formula for slope. So if you want the slope at a specific point, you take the derivative then plug in the x-coordinate into the derivative. And tangent line being horizontal means slope = 0. And since the derivative is a formula for slope, you want to find all the pointswhere the derivative = 0.

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