If y=1/x^2, find dy/dx|x=-2
Just do the deriv and input x=-2?
Yep.
1/4 :)
Looks good to me.
How would you find the deriv to this?
Without the whole x+h dealio
Well, this kind of derivative in particular has a pretty fast way of doing it. The long way would be that you need to make the x^2 into a negative exponent like this: \[\frac{ 1 }{ x ^{2} }=x ^{-2} \] Then you would use the power rule formula for derivatives, which is: \[x ^{n}\implies nx ^{n-1} \]So with n being -2, we use the formula to get: \[-2x ^{-3} =\frac{ -2 }{ x ^{3} } \] These fraction derivatives have a pattern tot hem, though, that make them a little easier.
That makes a lot of sense:)
Okay and how about finding a line tangent?
Oh wait a little different.. one sec:O
For the function, find the pts on the graph at which the tangent line is horiziontal. If none exist, state that fact.
Well, the derivative is a formula for slope. So if you want the slope at a specific point, you take the derivative then plug in the x-coordinate into the derivative. And tangent line being horizontal means slope = 0. And since the derivative is a formula for slope, you want to find all the pointswhere the derivative = 0.
Join our real-time social learning platform and learn together with your friends!