Question

At 9 am a car (A) began a journey from a point, traveling at 40 mph. At 10 am
another car (B) started traveling from the same point at 60 mph in the same
direction as car (A). At what time will car B pass car A?

Answer 1

I need help plz :)

Answer 2

9am the slow car started
10amm fast car started, and catching up wid the slow car

Answer 3

so, there is 1 hour difference

Answer 4

I want equation :()

Answer 5

in 1 hour, slow car wud have travelled 40 miles

Answer 6

and ?

Answer 7

say, after t hours both cars will meet

Answer 8

by that time,
slow car wud have travelled a distance of : 40 + 40t

Answer 9

fast car wud have travelled same distance of : 60t

Answer 10

ok ?

Answer 11

equate them

60t = 40 + 40t

Answer 12

solve t,
t is the time counted since the fast car started. so you must add 10am to watever t u get

Answer 13

ok

Answer 14

t = 2

Answer 15

?

Answer 16

Here's my approach:
Fast car is 1 hour behind (and 40miles behind) slow car but travelling 20 mph faster.
Basically, you have to determine how long it would take to travel 40 miles at 20mph.
gut ganeshie8 did a lot of work and has more equations.

Answer 17

so is t = 2 ?

Answer 18

t=2 is correct !

Answer 19

ganeshie8 i don't get it when you say "you must add 10am to watever t u get"

Answer 20

yes it will catch up in 2 hours since the fast car started so answering the problem, it will occur at 12:00 noon.

Answer 21

10am + 2 hours = 12 noon

Answer 22

oh ok thank guys !

Answer 23

np :)

Answer 24

u r welcome darkknight