Question

can anyone help me?
http://i.imgur.com/E86ZTKE.jpg

Answer 1

You want both ends to meet.

Answer 2

They have to be equal when \(x=1\) and \(x=3\)

Answer 3

@ineptAtMath Need more help?

Answer 4

let me try some stuff first. xD

Answer 5

is it, b=-4 and c =7?

Answer 6

I'm not sure how you got that answer, but it doesn't seem right.

Answer 7

awh ;'< then do u have anymore clues?

Answer 8

When \(x=1\) then you want: \[
(1)+1=(1)^2+b(1)+c
\]

Answer 9

This gives you the equation \[
2-1+b+c
\]

Answer 10

Use \(x=3\) to get the other equation.

Answer 11

ooopss i see what i did wrong

Answer 12

i accidently put (2) + 1

Answer 13

also, im too sure but how do u know ur suppose to use 3 and 1?

Answer 14

im not too sure*

Answer 15

Because that is where the function switches between pieces.\[
1<x<3
\]

Answer 16

i think i get it. thank you. :>