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Mathematics 7 Online
OpenStudy (anonymous):

Create a unique example of dividing a polynomial by a monomial. Explain, in complete sentences, the two ways used to simplify this expression and how you would check your quotient for accuracy.

OpenStudy (anonymous):

@Directrix

OpenStudy (anonymous):

is this a simple task in your eyes lol

Directrix (directrix):

First, make up a polynomial divided by a monomial. 4xyz² - 2x²y³ + xy ----------------- xy

Directrix (directrix):

Hit it with your best shot.

OpenStudy (anonymous):

i should use that one?

Directrix (directrix):

Make up your own if you want.

OpenStudy (anonymous):

im gonna just use that, but it seems tricy @Directrix

Directrix (directrix):

Instructive is how I describe it. It's okay by me if you make up your own.

OpenStudy (anonymous):

I think teh challenge is worth it.

OpenStudy (anonymous):

where do i take a wack at this first? i feel lost in a big one :D @Directrix

Directrix (directrix):

Factor the term (xy) out of all three terms of the numerator.

OpenStudy (anonymous):

4xyz² - 2x²y³ + xy ----------------- xy 4z^2 - 2xy^2

Directrix (directrix):

Almost. There are three terms in the numerator. There should be, in this case, three terms in the answer. Divide xy into xy. One xy is in the denominator and the other is in the numerator.

OpenStudy (anonymous):

so it stays as xy? 4z^2 -2xy^2+xy ?

Directrix (directrix):

No. xy/xy = 1. The answer is 4z² - 2xy² + 1

OpenStudy (anonymous):

okay, I'll keep that in mind.

Directrix (directrix):

So, the second way to do it is this: Reverse D.P. 4xyz² - 2x²y³ + xy xy( 4z² - 2xy² + 1) ----------------- = ----------------- = ( 4z² - 2xy² + 1) xy xy

Directrix (directrix):

For this --> check your quotient, we would multiply (xy) ( 4z² - 2xy² + 1) to show that we get back to the original problem (4xyz² - 2x²y³ + xy).

OpenStudy (anonymous):

same haha , goodnight @Directrix :D its so late again!

OpenStudy (anonymous):

Another successful tutoring.

OpenStudy (anonymous):

Help me on my question please

OpenStudy (anonymous):

alright, sounds good @Directrix take care. :)

OpenStudy (anonymous):

@Dailyinquirer12313213 which would that be?

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