Mathematics
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OpenStudy (user917):
If A, B are nonempty sets, and A ⊂ B, prove that A'
⊂ B'
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OpenStudy (anonymous):
Your mean is A dont have any thing and B too ?
OpenStudy (anonymous):
If it was your mean so A'=M
And B'=M
too :)
Got it ?:)
OpenStudy (user917):
What is mean?
OpenStudy (anonymous):
do you know M ?
OpenStudy (user917):
no we didn't study it yet
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OpenStudy (anonymous):
OK !
The M have all !
OK ?:)
M means mother and have all :)
Got it ?:)
OpenStudy (user917):
ok
OpenStudy (user917):
btw A' is the set that contains all limit points of A
OpenStudy (anonymous):
Exacly !
Because \[A=\phi\]
OpenStudy (anonymous):
It was =
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OpenStudy (anonymous):
And if we have B such as A so can say A=B
OK ?:)
OpenStudy (anonymous):
@user917:Got it ?:)
OpenStudy (user917):
But why A=ϕ ?
OpenStudy (anonymous):
Because u say that in problem :)
OpenStudy (anonymous):
That wasnt your mean ?????????
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OpenStudy (user917):
I said A, B are NONEMPTY set
OpenStudy (anonymous):
OK !
Are they =M ??or just none empty ?
OpenStudy (anonymous):
But dont need to know that :)
Wait ...
OpenStudy (anonymous):
Look A'= the things are not in A , A' have then :
AUA'=M
OK ?:)
GOT it :)?
OpenStudy (anonymous):
@user917:huh ????
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OpenStudy (user917):
and then?
OpenStudy (anonymous):
Got that ?:)
OpenStudy (user917):
wait a minute.. if A= { 2,85, 100} what is A' in this case?
OpenStudy (anonymous):
A' have all the things M has except 2,85,100
oK ?
OpenStudy (anonymous):
|dw:1063587086913:dw|
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OpenStudy (user917):
ok in this case if A is a bigger set than B that mean B' is a bigger set than A'
OpenStudy (anonymous):
what ???
OpenStudy (user917):
I think you're confusing between A' notation and A bar notation
OpenStudy (user917):
A' is the set that contain all the LIMIT points of A
OpenStudy (anonymous):
limit ???
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OpenStudy (user917):
Yes, a point p is called a limit point of a set E if every deleted
nbhd of p intersects E.
OpenStudy (anonymous):
LOOK !:
If we have :
M:{1,2,3,4,5,6}
then
A:{1,2}
A':{3,4,5,6}
OK ??...
OpenStudy (user917):
Are you sure?
OpenStudy (anonymous):
I m sure :)
Just remember this :)
OpenStudy (user917):
ok continue please :)
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OpenStudy (anonymous):
OK !
Now if A ⊂ B so B'⊂ A'
Because :
If we have :
M:{1,2,3,4,5,6,7,8,9}
B;{1,2,3,4,5,6}
A:{1,2,3}
A ⊂ B
So
A':{4,5,6,7,8,9}
B':{7,8,9}
So
B'⊂ A'
OK ?
OpenStudy (anonymous):
@user917:Got that ?:)
OpenStudy (user917):
Yes I got it
OpenStudy (user917):
but the question was prove that A' ⊂ B' and not B' ⊂ A'
OpenStudy (user917):
Sorry but I think you miss understand the question
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OpenStudy (user917):
A' is not A bar
OpenStudy (anonymous):
OK !
I think the proof say :
The A' ⊂ B' is not right :)
OpenStudy (anonymous):
Remember always M have both of A&A' and AUA'=M
OpenStudy (user917):
M have both A & A bar
OpenStudy (anonymous):
A&A'
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OpenStudy (user917):
|dw:1379251235439:dw|