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Mathematics 13 Online
OpenStudy (user917):

If A, B are nonempty sets, and A ⊂ B, prove that A' ⊂ B'

OpenStudy (anonymous):

Your mean is A dont have any thing and B too ?

OpenStudy (anonymous):

If it was your mean so A'=M And B'=M too :) Got it ?:)

OpenStudy (user917):

What is mean?

OpenStudy (anonymous):

do you know M ?

OpenStudy (user917):

no we didn't study it yet

OpenStudy (anonymous):

OK ! The M have all ! OK ?:) M means mother and have all :) Got it ?:)

OpenStudy (user917):

ok

OpenStudy (user917):

btw A' is the set that contains all limit points of A

OpenStudy (anonymous):

Exacly ! Because \[A=\phi\]

OpenStudy (anonymous):

It was =

OpenStudy (anonymous):

And if we have B such as A so can say A=B OK ?:)

OpenStudy (anonymous):

@user917:Got it ?:)

OpenStudy (user917):

But why A=ϕ ?

OpenStudy (anonymous):

Because u say that in problem :)

OpenStudy (anonymous):

That wasnt your mean ?????????

OpenStudy (user917):

I said A, B are NONEMPTY set

OpenStudy (anonymous):

OK ! Are they =M ??or just none empty ?

OpenStudy (anonymous):

But dont need to know that :) Wait ...

OpenStudy (anonymous):

Look A'= the things are not in A , A' have then : AUA'=M OK ?:) GOT it :)?

OpenStudy (anonymous):

@user917:huh ????

OpenStudy (user917):

and then?

OpenStudy (anonymous):

Got that ?:)

OpenStudy (user917):

wait a minute.. if A= { 2,85, 100} what is A' in this case?

OpenStudy (anonymous):

A' have all the things M has except 2,85,100 oK ?

OpenStudy (anonymous):

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OpenStudy (user917):

ok in this case if A is a bigger set than B that mean B' is a bigger set than A'

OpenStudy (anonymous):

what ???

OpenStudy (user917):

I think you're confusing between A' notation and A bar notation

OpenStudy (user917):

A' is the set that contain all the LIMIT points of A

OpenStudy (anonymous):

limit ???

OpenStudy (user917):

Yes, a point p is called a limit point of a set E if every deleted nbhd of p intersects E.

OpenStudy (anonymous):

LOOK !: If we have : M:{1,2,3,4,5,6} then A:{1,2} A':{3,4,5,6} OK ??...

OpenStudy (user917):

Are you sure?

OpenStudy (anonymous):

I m sure :) Just remember this :)

OpenStudy (user917):

ok continue please :)

OpenStudy (anonymous):

OK ! Now if A ⊂ B so B'⊂ A' Because : If we have : M:{1,2,3,4,5,6,7,8,9} B;{1,2,3,4,5,6} A:{1,2,3} A ⊂ B So A':{4,5,6,7,8,9} B':{7,8,9} So B'⊂ A' OK ?

OpenStudy (anonymous):

@user917:Got that ?:)

OpenStudy (user917):

Yes I got it

OpenStudy (user917):

but the question was prove that A' ⊂ B' and not B' ⊂ A'

OpenStudy (user917):

Sorry but I think you miss understand the question

OpenStudy (user917):

A' is not A bar

OpenStudy (anonymous):

OK ! I think the proof say : The A' ⊂ B' is not right :)

OpenStudy (anonymous):

Remember always M have both of A&A' and AUA'=M

OpenStudy (user917):

M have both A & A bar

OpenStudy (anonymous):

A&A'

OpenStudy (user917):

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