Question

Let f(x) =( 1/(x^3-2x)) . Then f' =

Answer 1

You know quotient rule?

Answer 2

i havent even learned that yet

Answer 3

Don't you know the formula (vdu-udv)/v^2 ???

Answer 4

no

Answer 5

nominate a "u" and a "v"

u = 1
v = x^3-2x

Answer 6

then derive both:

u' = 0

v' = x^3 - 2x

where you have to use product rule... for v'

do you know that rule?

Answer 7

u'v + v'u

Answer 8

^^ product rule

Answer 9

meh, i'll try it

Answer 10

u = x^3
v = -2x

so:

u' = 3x^2

v' = -2

Answer 11

so using product rule:

u'v + v'u

3x^2(-2x) -2(x^3)

Answer 12

simplified down:

-6x^3-2x^3

Answer 13

so using quotient rule:

(vu'-uv')/v^2