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Find each limit. Include a table of values to illustrate your answer. Include two tables if you need to consider a two sided limit.
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lim (1+x)^1/x as x--> 0
Okay what do you believe the limit to be?
1? i am not really sure though
@ceb105
Yes you are correct, the limit=1, your question would like you to explain this by putting in values around x=0, so input values of x=0.1, 0.01, 0.001 etc. Do this from both the above and below (positive a negative x values) to adequately show it. Alternatively, you know that Lim[x] x->0 = 0 therefore 1+Lim[x] x->0 = 1 => Lim[1+x] x-> 0 = 1 1^n where n is any real number will be 1. Thus as it will tend to 1 from above and below, the limit is 1
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