Question

lim x->0 Sin t / 1 + cos t = ?

Answer 1

There's nothing tricky there, it's a straightforward limit.

Answer 2

evaluation by substitution...

Answer 3

Unless you are saying its lim x->0 sin t/(1+ cos t)

Answer 4

That's how I interpreted it, but it's still straightforward.

Answer 5

yeah good point there heh

Answer 6

and I also of course assume it's the limit as t->0

Answer 7

yeah

Answer 8

sorry first time using this site, i am not sure i understand what you are saying

Answer 9

put in values and see what you get.

Answer 10

but you cant do that because if you plug the limit in you get 0

Answer 11

Sin t / 1 + cos t
t=0
0/(1+1)=0/2=0

Answer 12

Sin t / 1 + cos t
t=0
0/1+cos(0)=1

Answer 13

right, so is the limit 0?

Answer 14

I dunno, you didn't use parenthesis to indicate what you were trying to say and usually people get order of operations skewed

Answer 15

I know how you got to 0/2

Answer 16

its (sin t)/ 2+ cos t)

Answer 17

... you're missing a left parenthesis somewhere

Answer 18

2+ (cos t) is the denomiator

Answer 19

sorry denominator*

Answer 20

give me the entire expression with correct usage of parenthesis please -the answer varies greatly otherwise

Answer 21

lim x->0 (sin t)/ 1 + (cos t)

Answer 22

=0/1+1=1

Answer 23

0/2 is 0 not one

Answer 24

Based on this conversation I assume you're looking for
\[\lim_{t\rightarrow 0} \frac{\sin(t)}{1 + \cos(t)} = 0\]
The reason there is confusion, dom, is because when you write that you need to put the entire denominator in parentheses

lim t->0 sin(t) / (1 + cos(t) )

Answer 25

Is the answer 0?>

Answer 26

Yes, the answer is zero.

Answer 27

TY

Answer 28

0