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OpenStudy (anonymous):
How many moles of mgs2o3 are in 197g of the compound
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OpenStudy (anonymous):
There are 1.44 moles of mgs2o3 in 197g of the compund. To find this we took the number of grams of the compound we had (197) then divided by the moler mass of mgs2o3.(136.4343) So, the final equation was- 197g/136.4343
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