what is the equation in piont slope form of the line passing through(-2,0) and (2,8)?
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OpenStudy (anonymous):
use this formula:
\(\LARGE \color{blue} {\sf slope = \frac{ y _{2}\ - \ y _{1} }{ x _{2} \ - \ x _{1} }}\)
OpenStudy (anonymous):
and if you want the proof,i will prove it :)
OpenStudy (anonymous):
got it?
OpenStudy (anonymous):
yes kinda
OpenStudy (anonymous):
why kind of?
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OpenStudy (anonymous):
prove it
OpenStudy (anonymous):
ok,you know the slope is \(\sf \large\tan \theta\) ?
OpenStudy (mathstudent55):
This is the point-slope form of the equation of a line.
\( y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1} (x - x_1) \)
Just plug in your points into \(x_1, y_1, x_2, y_2 \)
OpenStudy (anonymous):
@mathstudent55 , using this formula is much better,i think!
finding the slope in your way , is difficult i think!
OpenStudy (anonymous):
@joebrown1 , ok?
so the slope in mathematics - or in physics - is tan theta .
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OpenStudy (anonymous):
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OpenStudy (anonymous):
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OpenStudy (anonymous):
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OpenStudy (anonymous):
can you continue?
OpenStudy (anonymous):
@joebrown1 , if you don't understand please just \( \sf \large {tell} \) me...:)