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OpenStudy (anonymous):
Mass, in grams, of 0.185mol sucrose (C12H22O11).
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OpenStudy (anonymous):
Can someone please show me how to do this problem?
OpenStudy (anonymous):
63.36g The molar mass of (C12H22O11) is 342.16. The molar mass tells how many grams are in one mole of the compound. So, since we have 0.185mol of (C12H22O11) we just multiply it by the molar mass. The final equation is 342.16 X 0.185 = 63.36g
OpenStudy (anonymous):
omg someone actually answered! thanks :)
OpenStudy (anonymous):
thats pretty easy.
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