Reaction of the anti-cancer drug cisplatin, Pt(NH3)2Cl2, with water is described by the equation
Pt(NH3)2Cl2(aq)+H2O(l)→ Pt(NH3)2(H2O)Cl+(aq)+Cl−(aq)
The rate of this reaction increases by a factor of 15 on raising the temperature from 25 ∘C to 50 ∘C.

what is the activation energy?

Question

Reaction of the anti-cancer drug cisplatin, Pt(NH3)2Cl2, with water is described by the equation 
Pt(NH3)2Cl2(aq)+H2O(l)→ Pt(NH3)2(H2O)Cl+(aq)+Cl−(aq) 
The rate of this reaction increases by a factor of 15 on raising the temperature from 25 ∘C to 50 ∘C. 

what is the activation energy?

aaronq · Answer

use the arrhenius equation:

$ln(\dfrac{k_1}{k_2})=\dfrac{E_a}{R}(\dfrac{1}{T_1}-\dfrac{1}{T_2})$

anonymous · Answer

what is the rate constant in this problem though? 15?

aaronq · Answer

it depends, if k1=1, then k2=15, or you can writ them the other way around.

aaronq · Answer

just make sure you're consistent with the temperatures.

anonymous · Answer

if K1=1 and K2=15, then t1=232 and t2=298?

aaronq · Answer

yeah, thats right. Make sure you write k in lower case, because capital K is the equilibrium constant.