Question

Easy College Algebra Question

Answer 1

I've never heard land described as "parcel".



Try using Pythagoras's theorem.

Answer 2

A^2 +B^2 =C^2
WIll do.

Answer 3

Your A could be "w+70" and your B "W" right?

Answer 4

50 & 120

Answer 5

@agent0smith , So far I have \[w^4+140w=12000\]
@DSS , thanks! I just want to be sure I can do it.

Answer 6

I do need help with the next step though.

Answer 7

Subtract 12000 from both sides, then either factor it, or use the quadratic formula.

but how did you get a w^4...?

Answer 8

I said \[(w+70)^2 +(w)^2 =(130)^2\]

I squared it from the get go.

Answer 9

So how'd you get w^4...? There shouldn't be one.

Answer 10

When you carry out \[(w+70)^2\] you get \[w^2+140w+4900\]

Answer 11

and then adding w^2 to that gave me w^4

Answer 12

Oh. You root it.

Answer 13

Is that it?

Answer 14

w^2 + w^2 = ...?

It's not w^4, you're combining like terms.

Answer 15

Got ya. Thank you.

Answer 16

Make sure you post your work so I or someone can check it.

Answer 17

I got 60 and 120. I said\[w^2 +140w-12000=0\] and factored.

Answer 18

Well, wolfram alpha factored.

Answer 19

I ment -200, not 120. My bad.

Answer 20

But can it be -200?

Answer 21

Your equation still isn't correct. Carefully expand out this: (w+70)^2 +(w)^2 =(130)^2

Answer 22

what's w+w equal to? 2w. What about w^2 + w^2?

Answer 23

2w^2

Answer 24

see your error now? \[\Large w^2 +140w-12000=0\]

Answer 25

Absolutely.

Answer 26

50 and 120.

Answer 27

Thank you so much.

Answer 28

Yep, but note you should only use w=50, not w=-120. The width is 50, not -120.

The length is 120, because w+70 = length. So 50+70 = 120 which is the length.