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Mathematics
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Limits and continuity
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If the function f is continuous everywhere and \[f(x)=\frac{ x ^{2}-16 }{ x-4 }\] when x does not equal 4, find the value of x
sorry, find the value of f(x)
Easy
Use difference of squares.
oh wait.. the answer is 8
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\[f(x) = \frac{ x^2 - 16 }{ x-4 } = \frac{ (x+4)(x-4) }{ x-4 } = x+4\]
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