f(x+1)^1 f(x)= 3x+2 I did it, but I have a question about the square root??
sorry, not square root, square
what is your question?
i did it like this f(x+1)^1 = 3(x^2+2x+1) + 2, but my teacher did it like this [3(x+1)+2]^2, why did he do that?
what are you trying to find in that equation? why is f(x+1) raised to the power of 1?
i did it like this f(x+1)^1 = 3(x^2+2x+1) + 2, but my teacher did it like this [3(x+1)+2]^2, why did he do that?
sorry, i meant power of two
so your question is what is f(x+1)^2 when f(x) = 3x+2?
no, my question is why did my teacher put the ^2 on the outside of the equation, like this [3(x+1)+2]^2
if that is what you mean than what you do is you substitute x with x+1 and then you square it, so f(x+1) = 3(x+1)+2, and since you have f(x+1)^2 it means you are squaring the entire function so you have (3(x+1)+2)^2
oh ok. I thought I was only squaring (x+1)
f(x) is one term so f(x)^2 = f(x)*f(x)
oh ok. thx
Join our real-time social learning platform and learn together with your friends!