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For the sequence given by an (a sub n) = 4n+5, find the first 4 terms of the sequence by substituting n=1,2,3,4 into the equation.
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me to the rescue lmao. a(1) = 4 + 5 = 9 a(2) = 8 + 5 = 13 a(3) = 12 + 5 = 17 a(4) = 16 + 5 = 21
9, 13, 17, 21?
yay!! :)
yes.
now how would i identify the 1st term and the 10th term of the sequence?
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would the first term be 9 and the last term is 4(10)+5?
yeah.
so 9 & 45 :D
mhm.
how would i use the first and tenth term to find the sum of the first tenth terms?
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S(10) = 1/2(45+9)(10) S(10) = 22(10) S(10)= 220
Understand what i did?
well with the 45+9, what happened to the 54?
the sum of the 10th term = 1/2(if a(1) + if a(10)) x 10 45+9 = 54 1/2(54) = 22
ahh i see now! thank you so much :)
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no problem.
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