Determine the mass (in g) of bromide ions in 5.99×10-3 mol of ammonium bromide.
find the total mass: \(n=\dfrac{m}{M}\) multiply the total mass by Br's mass percent composition
for determining the total mass, what is the mass (m)?
that's what you're finding.
plug in moles, and molar mass then solve for m (total mass).
Ah!
Mn=m (97.94g/mol)(5.99*10^-3)= 0.5867mol
or sorry, 0.5867g
thats good. now, find the mass percent composition of Br in the compound http://www.chem.tamu.edu/class/majors/tutorialnotefiles/percentcomp.htm
And how would I determine Br's mass percent composition?
oh ^^
(79.904g/mol)/(97.94g/mol)*100= 81.5846%
81.5846%*0.5867g= 47.8656
when you have percents you have to convert them into decimals: 81.5846 % = 0.815846 0.815846*0.5867g=
Right! So, 0.478656848g? (0.479g)
yep!
Yay!
Thank you!!
it feels good getting the right answer, doesn't it haha you're welcome !
It really does!
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