Question

limx-> 1 (1/x-3) + (1/x^2-3x+2)

Answer 1

\[ \dfrac{1}{x-3} + \dfrac{1}{x^2-3x+2}=-\dfrac{1}{x-1}+\dfrac{1}{x-2}+\dfrac{1}{x-3}\]

Answer 2

okay

Answer 3

give me the medal :3

Answer 4

lol
it is infinity

Answer 5

the second term has a zero in the denominator, and it doesn't go away when you add it to the first term, so the limit is infinite

Answer 6

yeah \[\lim_{x -> 1}\dfrac{1}{x-1}=\infty\]

Answer 7

hey what about my medal?

Answer 8

@darthjavier \to

Answer 9

\[\lim_{x\to 1}f(x)\]

Answer 10

\[\text{OKAY}\]

Answer 11

also \rigtharrow i think, but \to is shorter