Question

dy/dx of y=(sqrt(x)-1)/(sqrt(x)+1)

Answer 1

\[y=(\sqrt{x-1})/(\sqrt{x+1)}\]

Answer 2

is it?

Answer 3

@mathhelpkl

Answer 4

it's \[y=\sqrt{x}-1/\sqrt{x}+1\]

Answer 5

ok..ok

Answer 6

Do you knw the answer?

Answer 7

not quite...I'm really close though I think

Answer 8

where are you now on your solution?

Answer 9

I've gotten to \[y \prime=1/(\sqrt{x}+1) \] but I don't think that's quite right

Answer 10

* the bottom is squared

Answer 11

i am getting \[y'=1/(\sqrt{x}*(\sqrt{x+1})^2)\]

Answer 12

how did you get \[\sqrt{x}\] on the bottom