Question

Consider an n-sided regular polygon inscribed in a circle of radius r. Join the vertices of the polygon to the center of the circle, forming n congruent triangles
(a) Determine the central angle 0 in terms of n
(b) Show that the area of each triangle is ½ r^2 sin 0
(c) Let A n be the sum of the areas of the n triangles. Find lim A n n→∞

Answer 1

each angle measures 2π/n since the circle is divided into n equal angles

Answer 2

so the measure of Q is 2π / n

Answer 3

okay that makes sense now.

Answer 4

Show that the area of each triangle is ½ r^2 sin 0

Answer 5

that's for A, for B all u need to know is A = (1/2) base height

Answer 6

\[\triangle area = (1/2)r²\sin\]
\[Q = (1/2)r²\sin(2π/n)\]

Answer 7

and c is a bit confusing :P

Answer 8

Where it says An it should be a interval n

Answer 9

@ganeshie8 I need your help here!