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Mathematics 9 Online
OpenStudy (anonymous):

momentum and conservation

OpenStudy (anonymous):

p1 = (1/2)m2*3 = 1.5(m2) p2 = 2(m2)

OpenStudy (anonymous):

Hmm okay, so your equations are set up correctly. And you have the momentum of each of the pucks. Now what is it about momentum and conversation? How do these two terms relate?

OpenStudy (anonymous):

idk, p=mv i guess

OpenStudy (anonymous):

oh the final and initial momentum equals each other right

OpenStudy (anonymous):

Well that's just the equation you used for the two pucks:) It's more of a concept question. What is it about momentum that is special? It has to do with the conservation part

OpenStudy (anonymous):

the momentum before and after the collision is conserved

OpenStudy (anonymous):

There you go! In a closed system, the total momentum is conserved. So what we need first is the total initial momentum. We know the momentum for each puck, what is it as a total?

OpenStudy (anonymous):

hey what is closed system

OpenStudy (anonymous):

1.5 m2

OpenStudy (anonymous):

It just means that no other forces or factors are affecting the pucks. It comes from physics more so... but back to what I said, how can we calculate the total momentum of each puck?

OpenStudy (anonymous):

m*v = m1*3m/s

OpenStudy (anonymous):

Well that's just for one puck, we want the ''total'' momentum, meaning all the momentum from both pucks. Think of it this way, if I have 3 apples and 5 apples , my total apples is 8. Or another way, you have two objects, one has a mass of ikg, and the other 3kg. Your total mass is 4kg from everything. It's the same concept, in that we just want the total momentum!

OpenStudy (anonymous):

ohh 3.5m/s

OpenStudy (anonymous):

What did you calculate at the start of this problem?

OpenStudy (anonymous):

momentum of 2 pucks

OpenStudy (anonymous):

There you go :) but not 3.5 m/s We are dealing with momentum right now it would be 3.5 (m2)

OpenStudy (anonymous):

no would n't it be -0.5 (m2) m/s as they both are in opposite direction

OpenStudy (anonymous):

So that is our initial total momentum, now since momentum is conserved, the final momentum will also be 3.5 (m2)

OpenStudy (anonymous):

Ah, you are right in that regards I didn't see the opposite direction part.

OpenStudy (anonymous):

We can keep it positive for now, since we are not given any direction.

OpenStudy (anonymous):

Now remember the momentum equation?

OpenStudy (anonymous):

p=mv

OpenStudy (anonymous):

Yes! :P We are going to use that again. We know the momentum though, since it is conserved. Which is the 0.5 (m2) The unknown we are looking for is the velocity. What about the mass though? What would be the mass, if the two pucks are stuck together now?

OpenStudy (anonymous):

oh man...how to get that

OpenStudy (anonymous):

Well what was the mass of each puck, separately?

OpenStudy (anonymous):

1/2m2+m2=1.5m2

OpenStudy (anonymous):

Good!

OpenStudy (anonymous):

So that is our mass, so we have this....

OpenStudy (anonymous):

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