Question

if u =6Bcispi/3 and v =2Bcispi/4, write u/v in polar form

Answer 1

is B a constant

Answer 2

yeah

Answer 3

\[\frac{u}{v} = \frac{6B(\cos (\pi/3) +i \sin(\pi/3))}{2B(\cos (\pi/4) +i \sin(\pi/4))}\]
i believe the rule when dividing vectors is subtract the angles
\[\frac{u}{v} = 3[\cos(\pi/3 - \pi/4) +i \sin(\pi/3 - \pi/4)]\]

Answer 4

u/v = (6B/2B)?

Answer 5

yeah you divide the scalar "r" and subtract the angles

Answer 6

Oh sorry, it's meant to be 'cis' not 'cos'

Answer 7

"cis" is just shorthand for "cos + i sin"

Answer 8

oh

Answer 9

didnt know that lol

Answer 10

haha that might have been something your teacher should have gone over

Answer 11

so u/v = (6B/2B), cis (pi/3-pi/4)

= 3cis pi/12?

Answer 12

correct

Answer 13

Thanks

Answer 14

for the help

Answer 15

yw