Question

can somebody verify?

Answer 1

\[(3^{-1} -2^{-2})^{-2}\]

Answer 2

Just multiply the exponents and then subtract...

Answer 3

im gonna post my answer but just need to see if i am on the right track

Answer 4

post the steps, i'll verify it for you :)

Answer 5

3^2-2^4

Answer 6

That should be the answer

Answer 7

Simplify the negative exponents into fractions. Then you'll get the answer. Did you do that?

Answer 8

What does your name mean linux?

Answer 9

\[3^{-1 \times-2} \times -2^{-2 \times -2}\]
\[3^{2} \times -2^{4}\]
\[9 \times 16\]
144

Answer 10

correct

Answer 11

there's multiplication sign in between ? :O

Answer 12

where did you get the multiplication sign 'x' in the first step ?

Answer 13

that is not my name , that is just a way to say im an open source guy. i hate windows operating system and fell in love with ubuntu which is a linux system

Answer 14

haha oh yeah @hartnn , still gets answer

Answer 15

i just assume the should be a multiplication sign

Answer 16

Maybe the proper way of solving that is that simplify first your given number inside the parenthesis before you apply the laws of exponents. Btw, you got the right answer. :)

Answer 17

but since it isn't present n the Q , you should not just assume

Answer 18

you cant distribute the exponent like that when there is addition/subtraction inside parenthesis

Answer 19

how do you suggest i should tackle it , if you have to factors within a bracket you should do something with it , shouldnt i?

Answer 20

look at @Yttrium post

Answer 21

No dude. It should be (1/3 - 1/4)^-2

Answer 22

You have there negative exponents. Therefore, you need to reciprocate it to transform it into positive exponents which is simplifiable.

Answer 23

oh, yeah, you need to convert
the negative 2 power to positive 2
use, \(x^{-m}=1/x^m\)

Answer 24

\((3^{-1} -2^{-2})^{-2} = (1/3-1/4)^{-2 }=1/(1/3-1/4)^{2}=...?
\)

Answer 25

@Yttrium: \[(1 / 3 -1 / 4^2)^{-2}\]

Answer 26

that did not come out right

Answer 27

\[\left( \frac{ 1 }{ 3 }- \frac{ 1 }{ 4^{2} }\ \right)^{-2}\]

Answer 28

It's just [(1/3) - (1/4)]^-2
Remove the exponent beside 4. It's already simplified.

Answer 29

there should not be a 2 above 4
2^-2 itself is 1/4

Answer 30

thanks guys it now looks like something i can simplify

Answer 31

I realy dont know whats the question ???

Answer 32

the question is my first post at the top

Answer 33

Yea but thats not clear :...

Answer 34

thats exactly how it is in a question paper. you need to simplify

Answer 35

\[\left( 3^{-1}-2^{-2} \right)^{-2}\]
\[\left( \frac{ 1 }{ 3 }-\frac{ 1 }{ 4 } \right)^{-2}\]
\[\left( \frac{ 1 }{ 12 } \right)^{-2}\]
\[144\]

Answer 36

what ?
I cant see them ??...

Answer 37

refresh your browser

Answer 38

thanks guys

Answer 39

I m sorry :(