Mathematics
9 Online
OpenStudy (anonymous):
what is the braking distance if travelling 60km/h?
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OpenStudy (anonymous):
I didnt understand it well !
OpenStudy (dumbcow):
braking distance is proportional to speed squared...but you have to look up exact formula
OpenStudy (anonymous):
60km / h = 60x1000/3600 = 18.05m/s
OpenStudy (anonymous):
what formula am i supposed to use ??
OpenStudy (anonymous):
velocity is 18.05m/s
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OpenStudy (yttrium):
Well, if @dumbcow said it correctly. I think you need to do is to find the square root of your speed. :))
OpenStudy (anonymous):
how can i do that?
OpenStudy (yttrium):
You can use your calculator, if you're allowed. :D
OpenStudy (dumbcow):
ignore reaction time in formula
\[d = \frac{v^{2}}{\mu g}\]
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OpenStudy (dumbcow):
oops i forgot 2 in denominator
OpenStudy (anonymous):
@Yttrium your not helpful at all
OpenStudy (anonymous):
@dumbcow your a champ
OpenStudy (anonymous):
the answer in the textbook is 13.89m however im geting a different answer
OpenStudy (dumbcow):
check your conversion....60 km/hr = 16.666 m/s
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OpenStudy (anonymous):
D=(16.66)^2/2*u*g
OpenStudy (anonymous):
???
OpenStudy (dumbcow):
it could be a different "u" value...does book say anything about road surface or friction coefficient?
OpenStudy (anonymous):
no it doesnt
OpenStudy (anonymous):
something is missing from the formula
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ganeshie8 (ganeshie8):
looks book wants u to use g=10
OpenStudy (dumbcow):
yeah and u =1
thats only way you get their answer
ganeshie8 (ganeshie8):
assuming road is concrete, and tyres are rubber
u = 1 between Concrete & Rubber
OpenStudy (dumbcow):
the question should have specified those constants for you
OpenStudy (anonymous):
it hasnt i hate these textbooks
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OpenStudy (dumbcow):
using g=10 is not very precise
OpenStudy (anonymous):
it should be 9.81 but they should of specified