When formic acid is heated, it decomposes to hydrogen and carbon dioxide in a first-order decay: HCOOH(g) →CO2(g) + H2 (g) The rate of reaction is monitored by measuring the total pressure in the reaction container. Time (s) . . . P (torr) 0 . . . . . . . . . 220 50 . . . . . . . . 324 100 . . . . . . . 379 150 . . . . . . . 408 200 . . . . . . . 423 250 . . . . . . . 431 300 . . . . . . . 435 At the start of the reaction (time = 0), only formic acid is present. What is the formic acid pressure (in torr) when the total pressure is 291? half-life in sec? What is the rate constant (in s-1)?
pressure of formic acid=149torr,rateconstant=0.012s-1
You can tell by the units that the rate order is 1 (s\(^{-1}\))
but how did you get the answer? can you please write the steps thank you.
did u ask me?
do you know integral form of first order rate equation
[A] = [A]oe-kt ?
yes using that you can find k that is rate constant
take hcooh is A then[A]o=220torr
at50sec let HCOOH is xtorr used up then final HCOOH=220-x finalCO2=x,finalH2O=x but given total pressure is 324 torr at 50sec so220-x+x+x=324 x=104 [A]=220-x= 116 use them
if the total pressure is 291torr then 220-x+x+x=291 x=71 pressure of HCOOH=[A]=220-x=149
in such problems always assume x amount is used up and continue with given data
since one mole ofHCOOH gives one mole each of CO2 andH2O xamount also gives in same ratio
now is that clear to you shushu55
plz reply
oh i see so since Ao=220 I form an equation and set it equal to the give total pressure, in this case 291. Then I find x by solving the equation which is 71 & then again 220-71=149. Yep I think I got it thank you.
you're smart got it very fast
it took me 1month to find that technique
lol thanks:) you just explained it well. Trust me I'm lost in chemistry.
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