Question

Algebra

Answer 1

@ganeshie8

Answer 2

\(\huge \frac{x^{\frac{2}{3}}}{x^{\frac{4}{9}}}\)

Answer 3

Yeah but you need simplify that and Idk how exactly, don't you need to find the common denominator and stuff?

Answer 4

yep, lets work it step by step :)

first property we use :-

\(\large \color{red}{\frac{a^m}{a^n} = a^{m-n}}\)

when the base is same, we can subtract the exponents of a fraction

Answer 5

\(\huge x^{\left( \frac{2}{3} - \frac{4}{9}\right) }\)

Answer 6

We need to simplify it into radical form btw

Answer 7

yes that comes later

Answer 8

Okay, I was just making sure that it was mentioned c:

Answer 9

okay :) do the subtraction, in the exponenet

Answer 10

\[\frac{ -2 }{ -6 }\]

Answer 11

?

Answer 12

\(\huge x^{\left( \frac{2}{3} - \frac{4}{9}\right) }\)

\(\huge x^{ \left( \frac{ 2 \times 3}{3 \times 3} - \frac{4}{9} \right) } \)

\(\huge x^{ \left( \frac{ 6}{9} - \frac{4}{9} \right) } \)

\(\huge x^{ \left( \frac{ 6-4}{9} \right) } \)

\(\huge x^{ \left( \frac{ 2}{9} \right) } \)

Answer 13

check if i simplified the exponent correctly

Answer 14

I believe so, because you don't need to subtract the denominators if they're the same and well, 6-4 is 2

Answer 15

good, lets keep going

Answer 16

second property we use :-

\(\large \color{red}{ a^{\frac{m}{n}} = \sqrt[n]{a^m}}\)

Answer 17

\(\huge x^{ \left( \frac{ 2}{9} \right) } \)

\(\huge \sqrt[9]{x^{2}} \)

Answer 18

thats the final simplified form
notice that we oly had to use two exponent properties to simplify

Answer 19

Okay, thanks so much!

Answer 20

np :)