Question

A tennis ball with a velocity of 11.1 m/s is
thrown perpendicularly at a wall. After striking the wall, the ball rebounds in the opposite
direction with a speed of 9.3 m/s.
If the ball is in contact with the wall for
0.015 s, what is the average acceleration of
the ball while it is in contact with the wall?
Answer in units of m/s

Answer 1

i keep getting 120

Answer 2

\[a=\frac{ 9.3-(-9.3) }{ 0.05 }\]

Answer 3

372 meters per second??????????

Answer 4

m/s^2

Answer 5

over 800 mph

Answer 6

can you explain this to me please

Answer 7

acceleration is changing velocity in time. m/s is the velocity unit. If we divide it by second then we get m/s^2

Answer 8

i understand, but how can it travel at over 800 miles per hour

Answer 9

i dont think that us cirrect

Answer 10

mi/h is a velocity unit not acceleration.

Answer 11

yes but by your theory in one second the ball will increase velocity by over 800 mph

Answer 12

I am with zachy1234, I got 120, too

Answer 13

120 is wrong, this is a castle learning assignment and it said it was wrong

Answer 14

(11.1+9.3)/0.015 = 1360 m/s^2

Answer 15

i made a mistake about the time. It should have been 0,015 s

So, a=1240 m/s^2