PLEASE I CAN'T FAIL THIS ANYONE PLEASE!!!!!!!
you cant fail what?
Find the constant of variation for the quadratic variation.
x 2 3 4 5 6 y 24 54 96 150 216
Fail what?
y=6x^2
Write a quadratic variation equation if g(x) varies directly with x2, and g(x) = 144 when x = 6.
A direct variation is expressed by \(y = kx\) A direct variation with \(x^2\) is \(y = kx^2\) You need to find k. Use the given point to find k: \(g(x) = kx^2\) \(144 = k(6^2) \) Solve for k.
so K would be 24?
Notice the 6 is squared.
so the answer is g(x)= 6^2
Not quite. Can you solve the equation \(144 = k(6^2) \)? What do you get for k?
V varies inversely with T and V = 18 when T = 3. Which equation shows this relationship?
1. Did you ever finish the previous problem? 2. Please make a new post for each new question.
okay and yes I was 6x^2 and I got a 100%
but can some answer this anyways
V varies inversely with T and V = 18 when T = 3. Which equation shows this relationship?
\(144 = k(6^2)\) \( 144 = 36k\) \(k = 4\) \(g(x) = 4x^2\) is the correct answer.
okay
Inverse variation is given by \(y = \dfrac{k}{x} \) In this case, \(V = \dfrac{k}{T} \) Use the known point: V = 18 when T = 3 to find k: \(18 = \dfrac{k}{3} \) Solve for k.
Ya but the answers are either v=6/t v=6t v=54/t v=54t
sooo the answer is? V=6/t
\[\frac{ 6 }{ t }\]
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