help with composite figures medals will be given
for perimeter you add all the outsides
for the 1st picture P =21
For area, find the area of each smaller figure. Then find combine the sums of each.
@venomblast i got 18
I agree with @calliendra
3 sides of 3 one side of 4 and one side of 5
how? the perimeter of the square is 12 and the triangle base and hypotenuse is 9
you dont use the fourth side of the square since you have the triangle attached to it it is no longer a perimeter side
@Venomblast, only the outer segments of the figure counts as components of the perimeter.
i know it a perfect square of 3 in each side. the triangle of the base is 4 and the hypotenuse is 5
ohh.
if that the case, then yea 18
The figure really looks like this: |dw:1379365505927:dw|
so the perfect square has three sides of three ... one side of four and one side of five on the OUTSIDE .. ((one side of three on the square is attached to the other side of three on the triangle, but neither count since they are INSIDE)
Kassie - to find the area of this one do them separately -- use length X width to find the area of the square (3*3) and add it to the area of triangle which is (1/2)base*height ... to get area of everything keep in mind the BASE is the side attached to the square so it is 3 and the height is 4 (5 is the hypotenuse and not used in this equation) so it WOULD look like (3*3)+((1/2)*3*4)
for #2 it is similar adding the outside to get perimeter- you use length x width to get rectangle (0.5*3) and add it to the area of BOTH triangles. so find one and double it. (1/2)base x height the height is given below as 2 and the base is 3 looks something like (0.5*3)+((1/2)*2*3)+((1/2)*3*2)
for number three. is that a half circle on each side?
Join our real-time social learning platform and learn together with your friends!