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What is the solution to the rational equation 5 over x squared plus 3x plus 2 + 1 over x plus 2 = 1 over 3x plus 3
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\(\dfrac{5}{x^2+3x+2}+\dfrac{1}{x+2}=\dfrac{1}{3+3x}\) ??
|dw:1379365741558:dw|
Factor it, find an LCD, add up all the fractions, then see what you get.
i forgot i had to factor it
thanks i got it from here
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Ah, Kk. Yah, for the LCD. \(\dfrac{5}{(x+1)(x+2)}+\dfrac{1}{x+2}=\dfrac{1}{3(x+1)}\) The nice thing about the simple ones is the other terms give clues on the factoring.
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