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Integrate tan^3(x/4)sec^2(x/4)
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\[\Large \int \tan^3\left(\frac{x}4\right)\sec^2\left(\frac{x}4\right)dx\] It's like it's just begging for a substitution ^_^
\[\int\limits_{?}^{?}\tan ^{3}\frac{ x }{ 4 }\sec ^{2}\frac{ x }{ 4 }\]
Mine's better looking... anyway, the presence of a \(\large \sec^2\) which just happens to be the derivative of \(\large \tan\) may indicate that you use a substitution
Letting \(\large u = \tan\left(\frac{x}4\right)\) should do the trick :D
I'm guessing you already have an answer? :D
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Yes, thank you
Good :)
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