Question

lim as x -> 0+ for x/(ln(1-x^3))

Answer 1

Do I use L'Hopital or should I do it normally?

Answer 2

l'Hopital's since it it 0/0

Answer 3

That gives me 0, agreed? Or am I missing something?

Answer 4

0/0 does not equal zero.

nor does the limit as x->0+ after applying lHopital's

Answer 5

\[\frac{ f'(x) }{ g'(x) } = \frac{x^3 - 1 }{ 3x^2 }\]

Answer 6

What do I do when I get to -1/0 then? I guess that's where I got confused and for some reason just wrote it as equal to 0..

Answer 7

-1/0+ = - infinity = -1/0-

you can check on your calculator that 1/±0.0000000001 = a big number.

as the denominator gets infinitely smaller, 1/it approaches infinity

Answer 8

Ahhhhh. Apply it vice subbing in 0 all the time, aka think not plug-n-chug. Thank you

Answer 9

glad i could help :)