Question

Determine the thickness, in mm, of a 7.0 cm* 3.5 cm of a piece of aluminum foil if it has a mass of 0.1260 g.

Answer 1

We know that density is defined as\[\rho = {\rm mass \over \rm volume}\] We can find the thickness \(t\) as\[\rho = {m \over l \times w \times t}\] where \(l\) is the length and \(w\) is the width.

Answer 2

24.5 right

Answer 3

That doesn't seem right. What value for density are you using?

Answer 4

Try \(2.70 {\rm g \over cm^3}\)

Answer 5

The density, d, is mass, m, divided by volume, v.

\(d = \dfrac{m}{v} \)

That means the volume is

\(v = \dfrac{m}{d} \)

Using the mass of the piece of aluminum foil and the density of aluminum, can you find the volume of this piece of aluminum foil?

Answer 6

is it 24.5

Answer 7

No.

Answer 8

then can you show me how

Answer 9

as it is very hard to communicate through online. Can you just give me the solutions and anser without interuptions

Answer 10

and then ifi have any more questions. i will tellme teacher at school or at theend i will ask you any questions i have

Answer 11

Use the equation I gave above:

\(v = \dfrac{m}{d} \)

\(v = \dfrac{0.1260~g}{2.7 \frac{g}{cm^3}} \)

\(v = 0.0466666 ~cm^3\)

Answer 12

The next step is to find the thickness.

\(v = lwh\)

\(h = \dfrac{v}{lw} \)

\(h = \dfrac{0.046666~cm^3}{(7.0~cm)(3.5~cm)} \)

This will give you the height (thickness) of the piece of aluminum foil in cm.
Then you need to convert to mm.