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Mathematics 8 Online
OpenStudy (anonymous):

Can anyone please explain to me how to find the y-intercept? O.o

OpenStudy (debbieg):

The y-intercept is where the graph crosses the y-axis. For EVERY point on the y-axis, the x-coordinate of the point is x=0, So plug in x=0 in your equation, and solve for y. Tah-dah! That's your y-intercept (or, more technically, that's the y-coordinate of your y-intercept... and the x-coordinate, as I said, is x=0).

OpenStudy (anonymous):

put x value as 0 in the equation

OpenStudy (yttrium):

It's just the value of y when x is zero.

OpenStudy (anonymous):

solve the rest and you get the y intercept

OpenStudy (anonymous):

|dw:1063755879688:dw|

OpenStudy (anonymous):

Thankyou! :D I'll do that. :)

OpenStudy (anonymous):

The point line have an accident with y s !:)

OpenStudy (debbieg):

@E.ali I have no idea what you just said.... lol... :) Your diagram applies only to a linear equation, we don't know that she is working with a line. Other graphs have y-intercepts too. :)

OpenStudy (anonymous):

Is it the same with the x-intercept?

OpenStudy (debbieg):

Sort of, except now you have y-coordinate of 0, since you cross the x-axis. So set y=0, and solve for x. That's your x-intercept! :)

OpenStudy (anonymous):

Wha t?

OpenStudy (anonymous):

Thanks.. :)

OpenStudy (anonymous):

welcome ...

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