Question

Continuous Limit

Answer 1

@Luis_Rivera

Answer 2

@Hero

Answer 3

for it to be continuous, both "sub"-functions need to have the same value at 2.

so x^2 - c = 3x + 4c plugging in x = 2

4 - c = 6 + 4c

c = -2/5

Answer 4

how did you know to plug in 2, one of the functions x has to be less than 2 and the other has to be bigger than or equal to 2. The answer is correct btw i just want to make sure I understand the question

Answer 5

because were thinking about it in terms of limits. you're plugging in the left limit, or : 1.999999999999999999999999999999999999999999999999999 which is 2.

there can't be any holes in the function. it's why we observed it around 2

Answer 6

ok gotya thanks! its looks really confusing but now it isnt lol

Answer 7

glad i could help :)