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OpenStudy (anonymous):
The only class I take for FLVS showed an example of this kind of problem but gave it no solution and didn't tell you exactly how to solve it. They gave no other examples of what to do.
ganeshie8 (ganeshie8):
\(\large \sqrt{x-5}+7 = 11\)
ganeshie8 (ganeshie8):
subtract 7 both sides
OpenStudy (anonymous):
x-5=4 ?
ganeshie8 (ganeshie8):
who ate the radical ? :)
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OpenStudy (anonymous):
the 7-7 ?
ganeshie8 (ganeshie8):
\(\large \sqrt{x-5} = 4\)
OpenStudy (anonymous):
then do I square 4?
ganeshie8 (ganeshie8):
yup square both sides
OpenStudy (anonymous):
so x - 5 equals 16
then I add 5 to both sides? since it's substraction
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ganeshie8 (ganeshie8):
yup
OpenStudy (anonymous):
x=21 not extraneous
ganeshie8 (ganeshie8):
now plug that value and see if it satisfies.
slution wud be extraneous, if it doesnt satisfy the original equation
ganeshie8 (ganeshie8):
Yes, its not extraneous,
how u able to conclude that so fast
OpenStudy (anonymous):
I didn't solve it yet, I was going to type "or is it x=21 extraneous' but you were typing so I let you go first lol
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ganeshie8 (ganeshie8):
okay lol, plug x = 21 in original equation
ganeshie8 (ganeshie8):
if it satisfies the equation, the IT IS NOT EXTRANEOUS