Help worded question 3 only Please
@jdoe0001 can you help me please
well, they're really just asking for the inverse function, is all Pedro wants to know when[at what week] he will complete 30 assignments, he just dunnos what the inverse function of f(x) is
can you solve it for me cause I dont know how?
\(\bf f(x) = y = \cfrac{4x-3}{2}\quad\\ \textit{we get the inverse of it, by }\text{changing the letters}\\ \color{red}{y} = \cfrac{4\color{blue}{x}-3}{2}\quad \textit{inverse is}\quad \color{blue}{x} = \cfrac{4 \color{red}{y}-3}{2}\)
then just solve for "y" on the inverse
how do you solve for Y
well, there's the assumption you're supposed to know that by now
solve, or "isolate y"
okay let me try multiple both sides by 2?
yeap
2x=4y-3?
then what
add 3 to both sides
2x+3=4y next
divide both sides by 4
okay 2x+3/4
\(\bf x = \cfrac{4y-3}{2} \implies 2x = 4y-3 \implies 2x+3 = 4y\implies \cfrac{2x+3}{4} = y\)
is that the answer
2x+3/4=y
that's what Pedro needs, to plug in the assignments and get the "weeks" it'll take
do I have to do it for him plug the 30 into the x?
ohhh.. hmm, sure, yes, set x = 30, see how many weeks it takes, or see what "y" is
okay next one?
\(\bf y= \cfrac{2x+3}{4} \implies y= \cfrac{2(30)+3}{4} \implies y= \cfrac{60+3}{4}\ 15.75 so, 15 weeks and about day and a half
woops
\(\bf y= \cfrac{2x+3}{4} \implies y= \cfrac{2(30)+3}{4} \implies y= \cfrac{60+3}{4}\)
@jdoe0001 ? You there
she played 14hrs already she's restricted to 4 per week, only for 7 weeks if we make the weeks "x" f(x) = 4x but she already has 14hrs played from last week so f(x) = 4x + 14
well, you may want post anew, so we can all see it and help and revise each other gives more exposure, or more eyes :)
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