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Mathematics 20 Online
OpenStudy (dobby1):

HELP ME PLEASE MEDAL WILL BE GIVEN

OpenStudy (anonymous):

what is the question

OpenStudy (dobby1):

@zepdrix

OpenStudy (anonymous):

wuts the prob bro

OpenStudy (dobby1):

A cannery processed 1,445 pounds of strawberries in 4.5 hours. The cannery processed 2,320 pounds in 7 hours. Write a linear equation to model the relationship between the weight of strawberries S and time T. How many pounds of strawberries can be processed in 11 hours

OpenStudy (dobby1):

@zepdrix

OpenStudy (anonymous):

@funinabox

OpenStudy (dobby1):

funina box is offline

zepdrix (zepdrix):

Ok ok ok let's see here...

zepdrix (zepdrix):

Like the previous problem we did, this one can also be represented by a `linear function`. So we want to write something like this:\[\Large y=mx+b\] Err oh wait, do you have multiple choice for this one? Maybe we should look at those before we choose to jump into slope-intercept form.

OpenStudy (dobby1):

no i dont but i am not doing a graph either

zepdrix (zepdrix):

Ok let's just try it this way then :D For our problem we'll instead want to write it this way,\[\Large T=mS+b\]We're using the coordinates (S,T) instead of (x,y) for this problem. Try not to get too confused by that! :O

OpenStudy (dobby1):

ok

OpenStudy (dobby1):

i'll try wont be easy though lol

zepdrix (zepdrix):

XD

zepdrix (zepdrix):

From the information they gave us, we can write the relationships as ordered pairs. \[\Large (S_1,\;T_1) \quad =\quad (1445,\;4.5)\]\[\Large (S_2,\;T_2) \quad=\quad (2320,\;7)\]

zepdrix (zepdrix):

Remember how to find slope?? :D

OpenStudy (dobby1):

yeah

zepdrix (zepdrix):

It's gonna look a little weird since we're not using x and y. Hopefully it looks familiar though.\[\Large m=\frac{T_2-T_1}{S_2-S_1}\]

zepdrix (zepdrix):

So what do you get for your slope? :D

OpenStudy (dobby1):

\[m=\frac{ 7-4.5 }{2320-1445 }\]

OpenStudy (dobby1):

\[\frac{ 2.5 }{ 875 }\]

zepdrix (zepdrix):

Ok looks good. Let's multiply the top and bottom by 2, so we can get rid of the decimal.\[\Large m=\frac{5}{1750}\]

OpenStudy (dobby1):

why would we do that it is not in the equation so it could mess the equation up

zepdrix (zepdrix):

We didn't change the `value` of the fraction. We just changed how it looks. It's just easier to read now.

OpenStudy (dobby1):

ok

OpenStudy (dobby1):

we could do it as \[\frac{ 1 }{ 350 }\]

zepdrix (zepdrix):

oh nice! lol

OpenStudy (dobby1):

simplify it 2.5 goes into 875 evenly tada lol

zepdrix (zepdrix):

\[\Large T=mS+b\qquad\to\qquad T=\frac{1}{350}S+b\]To find b, we simply plug in one of our ordered pairs and solve for it! \[\Large 7=\frac{1}{350}(2320)+b\]

OpenStudy (dobby1):

ok what next?

zepdrix (zepdrix):

So what do you get for \(\Large b\) ? :D solve the equation!!

OpenStudy (dobby1):

.371528

zepdrix (zepdrix):

Yah, let's leave it as a fraction for right now I guess. \[\Large b=\frac{130}{350} \qquad\to\qquad b=\frac{13}{35}\]

OpenStudy (dobby1):

ok what next?

zepdrix (zepdrix):

So we've successfully found a linear equation for our relationship.\[\Large T=mS+b \qquad\to\qquad T=\frac{1}{350}S+\frac{13}{35}\]

zepdrix (zepdrix):

The next part of the question is asking us, when \(\Large T=11\), solve for \(\Large S\)

OpenStudy (dobby1):

\[11=\frac{ 1 }{ 350 }S+\frac{ 13 }{ 35 }\]

OpenStudy (dobby1):

@thomaster

OpenStudy (dobby1):

@phi @jim_thompson5910 @ganeshie8

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