HELP ME PLEASE MEDAL WILL BE GIVEN
what is the question
@zepdrix
wuts the prob bro
A cannery processed 1,445 pounds of strawberries in 4.5 hours. The cannery processed 2,320 pounds in 7 hours. Write a linear equation to model the relationship between the weight of strawberries S and time T. How many pounds of strawberries can be processed in 11 hours
@zepdrix
@funinabox
funina box is offline
Ok ok ok let's see here...
Like the previous problem we did, this one can also be represented by a `linear function`. So we want to write something like this:\[\Large y=mx+b\] Err oh wait, do you have multiple choice for this one? Maybe we should look at those before we choose to jump into slope-intercept form.
no i dont but i am not doing a graph either
Ok let's just try it this way then :D For our problem we'll instead want to write it this way,\[\Large T=mS+b\]We're using the coordinates (S,T) instead of (x,y) for this problem. Try not to get too confused by that! :O
ok
i'll try wont be easy though lol
XD
From the information they gave us, we can write the relationships as ordered pairs. \[\Large (S_1,\;T_1) \quad =\quad (1445,\;4.5)\]\[\Large (S_2,\;T_2) \quad=\quad (2320,\;7)\]
Remember how to find slope?? :D
yeah
It's gonna look a little weird since we're not using x and y. Hopefully it looks familiar though.\[\Large m=\frac{T_2-T_1}{S_2-S_1}\]
So what do you get for your slope? :D
\[m=\frac{ 7-4.5 }{2320-1445 }\]
\[\frac{ 2.5 }{ 875 }\]
Ok looks good. Let's multiply the top and bottom by 2, so we can get rid of the decimal.\[\Large m=\frac{5}{1750}\]
why would we do that it is not in the equation so it could mess the equation up
We didn't change the `value` of the fraction. We just changed how it looks. It's just easier to read now.
ok
we could do it as \[\frac{ 1 }{ 350 }\]
oh nice! lol
simplify it 2.5 goes into 875 evenly tada lol
\[\Large T=mS+b\qquad\to\qquad T=\frac{1}{350}S+b\]To find b, we simply plug in one of our ordered pairs and solve for it! \[\Large 7=\frac{1}{350}(2320)+b\]
ok what next?
So what do you get for \(\Large b\) ? :D solve the equation!!
.371528
Yah, let's leave it as a fraction for right now I guess. \[\Large b=\frac{130}{350} \qquad\to\qquad b=\frac{13}{35}\]
ok what next?
So we've successfully found a linear equation for our relationship.\[\Large T=mS+b \qquad\to\qquad T=\frac{1}{350}S+\frac{13}{35}\]
The next part of the question is asking us, when \(\Large T=11\), solve for \(\Large S\)
\[11=\frac{ 1 }{ 350 }S+\frac{ 13 }{ 35 }\]
@thomaster
@phi @jim_thompson5910 @ganeshie8
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