Question

Help please I THINK I got it. Write the equation in point-slope form and slope-intercept form. Graph shown below.

Answer 1

Neither of those two points is on the line.

Answer 2

Then where does the line pass through? 1?

Answer 3

Look at the y-axis. Where does the line cross the y axis?

Answer 4

3?

Answer 5

Correct. That means one point on the graph is (0, 3).
Now we need another point.

Answer 6

The point where the graph crosses the x axis is between two grid lines, so it's hard to read the value.

Can you find a point on the line that is on both a vertical grid line and a horizontal grid line? This way it'll be easy to read both the x- and y-coordinates.

Answer 7

Does that have to be a fraction?

Answer 8

No. If the point is on grid lines, there are no fractions.

Answer 9

On both? I'm kinda lost. It's between -1 and -2?

Answer 10

-1, 1?

Answer 11

What is? I asked you to find a point that lies on grid lines, not in between lines.

Answer 12

Yes, that's it. (-1, 1) lies on grid lines. Great.

Answer 13

Now we have two points that lie on the line.
(0, 3) and (-1, 1)

Answer 14

\[m = \frac{ 3 - 1 }{ 0 - -1 }\]

Answer 15

The point slope form is:

\(y - y_1 = m(x - x_1) \)

where m is the slope and (x_1, y_1) is a point on the line.

Answer 16

Your slope is good, now combine terms in the numerator and denominator.

Answer 17

m = 2

Answer 18

Great.
Now use the point-slope equation I wrote above. Use either point for \( (x_1, y_1) \) and use 2 for the slope.

Answer 19

\(y - y_1 = m(x - x_1) \) using \((x_1, y_1) = (-1, 1) \) and \(m = 2\) you get:

\(y - 1 = 2(x - (-1) ) \)

\(y - 1 = 2(x + 1) \)

This is the equation in point-slope form.

Answer 20

The slope-intercept form is:

\(y = mx + b\)

where m = slope (it's 2 in this problem), and
b = the y-intercept (it's 3 in this problem)

so \(y = mx + b\) becomes

\(y = 2x + 3\)

This is the equation is slope-intercept form.

Answer 21

gtg, bye