Question

A 2000 kg car experiences a constant braking
force of 10,000 N, and comes to be a stop in 6
sec.
What would be the distance traveled by the
car in coming to rest?

Answer 1

so f=ma

Answer 2

and \[a=\frac{ \Delta v }{ \Delta t }\]

Answer 3

How do I relate this to distance?

Answer 4

so we know that our v final is 0

Answer 5

and so we have have for our equation now\[10,000=2,000*\frac{ v-0 }{ 6 }\]
you want to solve for v

Answer 6

and then we can use the equation for one dimensional to solve for \[\Delta x\]

Answer 7

that equation would be \[\Delta x=\frac{ 1 }{ 2 }(v+v _{0})t\]

Answer 8

So the answer is 90 m?

Answer 9

I got the same thing when I plugged it in, so I would say so

Answer 10

or wait i made a slight error

Answer 11

but it does not affect the out put

Answer 12

Thank you for the help :)

Answer 13

it is just the placement of the zero before so it should be\[10,000=2,000*\frac{ 0-v _{0} }{ 6 }\]

Answer 14

you are welcome