Question

I can't remember how to do this algebra, can someone please help:

Answer 1

\[\frac{ \sqrt{t} }{ t^{2} }\]

Answer 2

what do you want to do here?

Answer 3

well it's for a limit problem, and i need to divide this. . i can't remember how T__T

Answer 4

what's the full problem?

Answer 5

\[\lim \frac{ \sqrt{t} +t^{2}}{ 2t-t^{2} } \]

Answer 6

as t -> infty

Answer 7

I'm suppose to divide the t^{2} with everything right?

Answer 8

ok I see what's going on, one sec

Answer 9

okay

Answer 10

I would use the idea that

\[\large \sqrt{t} = t^{1/2}\]

Answer 11

to turn

\[\large \frac{ \sqrt{t} }{ t^{2} }\]

into

\[\large \frac{ t^{1/2} }{ t^{2} }\]

\[\large t^{1/2-2} \]

\[\large t^{1/2-4/2} \]

\[\large t^{-3/2} \]

Answer 12

i see, is the rule to subtract exponents?

Answer 13

oh wow i remember now thanks so much!

Answer 14

see where to go from there?

if so, then what's the final answer?

Answer 15

gonna need a minute lol

Answer 16

ok

Answer 17

hey jim, the book says -1 , but I got positive one.

my answer is: \[\frac{ \sqrt{\frac{ -3 }{ t }}+1 }{ \frac{ 2 }{ t } + 1}\]

Answer 18

when the denominator is has the variable, then it should be zero right?

Answer 19

shouldn't it be 1/1?

Answer 20

\(\large 2t-t^{2}\) in the denominator should turn into \(\large \frac{ 2 }{ t } - 1\) after you divide everything by \(\large t^2\)

Answer 21

ohhhhh my goodness i see!

Answer 22

huge error on my part. . . thanks so fricking much jim!

Answer 23

you're welcome

Answer 24

and it wasn't so huge, silly typo really