What is the largest possible area for a rectangle with a perimeter of 80 cm?
How do I do this?
|dw:1379456691445:dw|
assumed that rectangle be a square what is the area of a square which has perimeter = 80 ?
you have to determine its side of the square
@RadEn it would be 20 each side if it was a square
Imagine one side is X. The other side will be Perimeter/2-X=40-X Area will be: \[A=X·(40-X)=40X-X^2\]Find the maximum for the function A: \[dA/dX=0 \rightarrow 40-2X=0 \rightarrow X=20\]So one side is X=20 and the other 40-X=20. It is a square with side 20---->Max Area=400
yes, so the area = side * side = 20 * 20 = 400
yes it would be 400 @RadEn
wait?! @RadEn @CarlosGP okay so I have ....
okay, is it like this
|dw:1379457001169:dw| ?????
No, it is x and 40-x
oh ya huh haha okay sorry about that. let me try again
|dw:1379457088942:dw| ? like this?
@CarlosGP
Yes, so the area is A=x·(40-x) right?
yes it is. haha sorry i was looking at it again
You cannot say it is a square, you need to prove it has to be a square. Then find the maximum of the polynomial function A=x(40-x) and you will get that happens when x=20
okay, cuz if it was a square it would be easier. but in this case the answer would be as you say A=x(40-x) right? because half of 80 is 40, and we have to subtract x from that 40 because we do not know what x is exactly. @CarlosGP
@CarlosGP
That is right.
YAY!!! THANK YOU!! :D okay, i have one more question im going to post.
u r welcome! Please, close this one and create a new post
I already did :)
the rectangle would has the largest area if its length = width that's the property of a square, no prove here because obviouly would has same answer if you do by using calculus :) @CarlosGP
More useful to learn calculus than learning by heart the properties of a rectangle
depent what level the student is studying it. if just for basic, i think calculus not yet ready get it . note : "if the length of rectangle not same with the width, the area cant be maximum." for @lilsis76
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