Question

Hey! I'm stuck on some problems on my homework.
1. Find the following limit.
lim as x approaches infinity of (square root of 36x squared +x -6x) note: -6x is outside the square root.

Answer 1

\[\lim_{x\rightarrow\infty}{[\sqrt{3x^2+x}-6x]}\]
Is that it?

Answer 2

yes. i don't know how to write it like that lol

Answer 3

Haha its the code of LaTex. Learn it then practice using it because it can simplify things a lot and write equations with any complexity. For example:
\[y=\left[(1-n)\frac{\int{e^{(1-n)\int{p(x)dx}}q(x)}+c_1}{e^{(1-n)\int{p(x)dx}}}\right]^{\frac{1}{1-n}}\]

Lol so its pretty neat. Anyways. back to the question. I haven't even began simplifying anything, but graphically, it appears:
\[\lim_{x\rightarrow\infty}{\sqrt{3x^2+x}-6x}=-\infty\]

Answer 4

Where is the LaTex code located? and how did you get -infinity ??

Answer 5

Well I mean, some sites worth checking out are:
http://www.latex-project.org/guides/
http://www.mathjax.org/resources/docsindex/
And I said just by graphing it, it looks like that

Answer 6

ok thanks alot :)