On a street with 24 houses, 9 houses have fewer than 6 rooms, 8 houses have more than 7 rooms, and 4 house have more than 8 room. What is the total number of houses on the street that are either 6-, 7- or 8-room houses? 8 9 11 13 14
So, how far did you get with this?
i had got 11 and it wqas wrong
I was in the process of replying on your OTHER post of this same question when you closed it. I'll try again.
They key here is you are lookng for things that are from 6 to 8, right? So what in the information excludes parts of that?
Starting with 24 houses, 9 have FEWER than 6 rooms. So those are NOT in the category of 6, 7 or 8 room houses, so eliminate those. That leaves 24 - 9 =15 houses to consider.
Since 8 houses have MORE THAN 7 (includes the 8-room houses that we want to count), and 4 houses have MORE THAN 8 (which we DONT want to include in our count), that tells us to eliminate how many more, from the 15 we are now down to?
14
How did you get 14?
If 8 have more than 7, and 4 have more than 8, then how many of the 8 that have more than 7, do we need to eliminate from our count?
We WANT the 8-room houses, but not the more-than-8-room houses. If 8 houses have more than 7, and 4 have more than 8, then how many MORE houses should we EXCLUDE from our count?
hmmmm.... you say that you answered 11 and it was wrong?
yea
Well, lets see what @e.mccormick says, because I think that's the correct answer too. lol
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Becaue you are looking for 6, 7, and 8, you need to see what eliminates more than 8 and less than 6. Any data that talks about more than 7 is extraneous.
Oh, and there are exactly 4 houses with 8 rooms, but that doe not matter.
it's 11
You start with 24. You eliminate: 9 that have fewer than 6 rooms 4 that have more than 8 rooms So that's 9+4=13 24 - 13 = the ones that have 6 - 8 rooms.
Yes. There are 11. So if you answered that, it is correct.
So yah, you are not crazy and 24-9-4=11 is still true.
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